SOLUTION: A tractor of mass 5*10^3kg is used to Low a car of mass 2.5*10^3kg. The tractor moved with a speed of 3.0m/sec just before the towing rope becomes taut. Calculate (1) speed of th

Algebra ->  Formulas -> SOLUTION: A tractor of mass 5*10^3kg is used to Low a car of mass 2.5*10^3kg. The tractor moved with a speed of 3.0m/sec just before the towing rope becomes taut. Calculate (1) speed of th      Log On


   

Question 1073146: A tractor of mass 5*10^3kg is used to Low a car of mass 2.5*10^3kg. The tractor moved with a speed of 3.0m/sec just before the towing rope becomes taut. Calculate
(1) speed of the tractor immediately the rope become taut.
(2) loss in K. E of the system just after the car has started moving.
(3) impulse in the rope when it jerks the car into motion.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
a) Using conservation of momemntum,
m%5Bt%5D%2Av%5Bt1%5D=%28m%5Bt%5D%2Bm%5Bc%5D%29v%5B2%5D
v%5B2%5D=%28m%5Bt%5D%2Av%5Bt1%5D%29%2F%28m%5Bt%5D%2Bm%5Bc%5D%29
v%5B2%5D=%285x10%5E3%2A3%29%2F%285x10%5E3%2B2.5x10%5E3%29
v%5B2%5D=%285%2F7.5%29%283%29
v%5B2%5D=2m%2Fs
.
.
.
b) KE%5B1%5D=%281%2F2%29m%5Bt%5Dv%5B1t%5D%5E2
KE%5B1%5D=%281%2F2%295x10%5E3%283%5E2%29
KE%5B2%5D=%281%2F2%297.5x10%5E3%282%5E2%29
DELTA%2AKE=KE%5B2%5D-KE%5B1%5DJ
.
.
c) Use the change in momentum of the car to calculate the impulse,
I=2.5x10%5E3%282-0%29%28kg%2Am%29%2Fs
.
.
.
Complete the calculations in b and c.