Question 1048028: (a) the ratio of mr paul's salary to mrs anna's salary is 3:4. if mrs anna draws a salary of Rs 28000, find mr. paul's salary.
(b) an amount of Rs210 is shared between roy and shireen so that ro gets 2/5 of shireen's share. how much does shireen get ?
(c) in a school of 540 pupils, there are 5 girls to every 4 boys. how many boys are there in that school ?
Found 4 solutions by mananth, greenestamps, ikleyn, josgarithmetic:
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! a) the ratio of mr paul's salary to mrs anna's salary is 3:4. if mrs anna draws a salary of Rs 28000, find mr. paul's salary.
mr paul's salary / mrs anna's salary =3/4
mr paul's salary t/ 20000 =3/4
mr paul's salary =20000 *3/4
= Rs. 15000
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Set up all three problems the same way, using the given ratios.
(a) the ratio of mr paul's salary to mrs anna's salary is 3:4. if mrs anna draws a salary of Rs 28000, find mr. paul's salary.
The ratio 3:4 is given in the statement of the problem. Use it like this to set up the problem:
Let 3x = Mr Paul's salary
Let 4x = Mrs Anna's salary
Mrs Anna's salary is Rs 28000:
4x = 28000
...
(b) an amount of Rs210 is shared between roy and shireen so that ro gets 2/5 of shireen's share. how much does shireen get ?
Here you have to do some interpretation of the given information to find that the ratio of the two amounts is 2:5. Then...
Let 2x = Roy's amount
Let 5x = Shireen's amount
The total is Rs 210:
2x+5x=210
...
(c) in a school of 540 pupils, there are 5 girls to every 4 boys. how many boys are there in that school ?
Only a little bit of work is needed to see that here the ratio is 5:4. So...
Let 5x = number of girls
Let 4x = number of boys
The total number of pupils is 540:
5x+4x = 540
...
Finishing each of the problems is easy, using basic algebra. For example, for the first problem....
4x = 28000
x = 28000/4 = 7000
ANSWER: Mr Paul's salary is 3x = 3(Rs 7000) = Rs 21000
You can finish the other two problems.
Answer by ikleyn(52788)  (Show Source):
You can put this solution on YOUR website! .
The solution and the answer (Rs.15000) to part (a) in the post by @mananth both are incorrect.
Ignore his post for your safety.
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and work against yourself.
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from which you post your problems.
As you can learn from it, only ONE problem is allowed per post.
Please do not violate this rule.
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Answer by josgarithmetic(39618)  (Show Source):
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