SOLUTION: If the surface of a cube is 6x^2 -36x +54, what is the expression for the volume of the cube?

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Question 1027670: If the surface of a cube is 6x^2 -36x +54, what is the expression for the volume of the cube?
Found 3 solutions by mananth, Theo, ikleyn:
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2 -36x +54
area = 6l^2
Volume = l^3
(6x^2 -36x +54)/6 =l^2
x^2-6x+9=l^2

(x_3)^2=l^2
l=(x-3)
Volume = (x-3)^3

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
formula for surface area of a cube is 6s^2.

s represents the length of the side of the cube.

that means that 6s^2 = 6x^2 - 36x + 54.

divide both sides of this equation by 6 and you get:

s^2 = x^2 - 6x + 9

factor that quadratic equation on the right side of the equation and you get:

s^2 = (x-3) * (x-3) = (x-3)^2

take the square root of both sides of the equation to get:

s = plus or minus (x-3).

since s can't be negative, then s = (x-3).

note that the value of x would have to be greater than 3, otherwise the length of the side would be negative.

the formula for the volume of a cube is s^3.

that means the volume of the cube must be equal to (x-3)^3.

since (x-3)^2 = x^2 - 6x + 9, then (x-3)^3 must be equal to:

(x-3) * (x^2 - 6x + 9) which would then be equal to x^3 - 9x^2 + 27x - 27.

how do you confirm this is correct?

assume the side of the cube is equal to 5 units.

the surface area would be 6s^2 = 6 * 5^2 = 6 * 25 = 150 square units.

the volume would be s^3 = 5^3 = 125 cubic units.

we had previously shown that s = x-3.

this means that x = s + 3.

if s = 5, this means that x = 8.

our formula for surface area is 6 * s^2 = 6.

since s = (x-3), then the surface area = 6 * (x-3)^2 = 6x^2 - 36x + 54.

replace x with 8 in these formulas and you will see that 6 * (x-3)^2 = 6 * 5^2 = 6 * 25 = 150 square units.

you will also see that 6x^2 - 36x + 54 = 6 * 8^2 - 36 * 8 + 54 = 384 - 288 + 54 = 150 square units.

the volume of the cube is equal to s^3.

when s = 5, this gets you the volume of the cube = 125 cubic units.

when s = 5, x = 8.

the volume of the cube = (x-3)^3 = (8-5)^3 = 5^3 = 125 cubic units.

the volume of the cube is also equal to x^3 - 9x^2 + 27x - 27.

when x = 8, this becomes (8)^3 - 9*8^2 + 27*8 - 27 which becomes equal to 512- 576 + 216 - 27 which becomes equal to 125 cubic units.

the formulas look good.

the expression for the volume of the cube would be (x-3)^3 or x^3 - 9x^2 + 27x - 27, depending on how you want to show it.

Answer by ikleyn(53742) About Me  (Show Source):
You can put this solution on YOUR website!
.
If the surface of a cube is 6x^2 -36x +54, what is the expression for the volume of the cube?
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        I will give different solution from that by @mananth and from that by @Theo,
        and at the end I will explain why the solutions by both these tutors are incorrect and why they should be changed.


The surface area of the cube is given by the polynomial expression  6x^2 - 36x + 54.


It is the combined area of 6 identical faces of the cube.  
The area of each face separately is

    (6x^2 - 36x + 54)/6 = x^2 - 12x + 9 = (x-3)^2.


Notice that the given polynomial is always non-negative, 
so its values make sense as the face area for all values of x =/= 3.


The length of the side of this cube is  sqrt%28%28x-3%29%5E2%29 = |x-3|.


Notice that I use the absolute value  |x-3|  here, 
as the length is always assumed to be non-negative.


The volume of the cube is then  abs%28x-3%29%5E3.


This formula works for all values  x =/= 3, including  x < 3, 
while the formulas in the posts by @mananth and by @Theo do not work at x < 3 (!)
giving negative values for the edge length and for the volume.


So, my solution is MORE UNIVERSAL and more ACCURATE than the @mananth' solution and/or than the @Theo' solution.

Actually, this seemingly simple task has a  highlight%28highlight%28well%29%29  highlight%28highlight%28hidden%29%29  murderous  highlight%28highlight%28trap%29%29.

My solution discloses the trap, teaches you on how to avoid this trap
and also teaches you to be always aware and always accurate in Math.


------------------------------

        It is   I N T E R E S T I N G


Today,  on  Feb.14,2026,  I submitted this problem to  GOOGLE  AI  Overview to see how it treats it.

Google AI Overview practically repeated incorrect/incomplete solution by @mananth and by @Theo.

Naturally,  I reported to  Google  AI  about their fault through their feedback system.


Then I made my next experiment. I submitted the same problem to other AI,
math-gpt.org , which (i think) is slightly more advanced.

This other AI repeated the same tediousness and produced the same "lame" solution
(which reminds me a lame horse with three legs).

It is the real world of AI in the area of solving school Math problems, in which we all live now.