Question 1011843: xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2 Found 4 solutions by addingup, ikleyn, MathTherapy, Fombitz:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! (x^2+y^2)=25 take the square root on both sides:
x+y= 5
(x+y)2^2 and since x+y= 5:
5(2)^2= 5(4)= 20
You can put this solution on YOUR website! .
xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2 ?
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xy=12, = implies that
= + = 25 + 2*12 = 25 + 24 = 49.
Again:
= = 49.
So, if you need , you just have it: it is 49.
What you do REALLY need, I don't know, because you do neglect to use parentheses properly.
If it is , then it is equal to 4*49.
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Observing , it's obvious that x and y MUST be 3 and 4
Likewise x and y MUST be 3 and 4 as xy = 12
Proving this, we get: --------> , which becomes: 25 + 2(12) = 25 + 24 = 49
Since , then x + y = 7 ------ Square root of each side was taken
I don’t know what means but you should be able to determine what’s needed since it was found that: & , and the following were given: &
