SOLUTION: Show that the square of the sum of two numbers minus the square of their difference is equal to four times their product. let a represent one number and b represent the other numbe

Algebra ->  Expressions -> SOLUTION: Show that the square of the sum of two numbers minus the square of their difference is equal to four times their product. let a represent one number and b represent the other numbe      Log On


   

Question 815343: Show that the square of the sum of two numbers minus the square of their difference is equal to four times their product. let a represent one number and b represent the other number.
Thank you to whomever solves this problem.
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
(a + b)(a + b) - (a - b)(a - b) = 4ab
(a + b)(a + b) - (a - b)(a - b)
aa + 2ab + bb - (aa - 2ab + bb)
aa + 2ab + bb - aa + 2ab - bb
2ab + 2ab
4ab
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