SOLUTION: Wendy bought 7 bags. Each bag costs the same amount. She paid the cashier $90 and received g dollars as change. What was the cost of each bag in terms of g?

Algebra ->  Expressions -> SOLUTION: Wendy bought 7 bags. Each bag costs the same amount. She paid the cashier $90 and received g dollars as change. What was the cost of each bag in terms of g?      Log On


   

Question 750911: Wendy bought 7 bags. Each bag costs the same amount. She paid the cashier $90 and received g dollars as change. What was the cost of each bag in terms of g?
Found 2 solutions by jim_thompson5910, FrankM:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
let b = cost of each bag

Since she bought 7 bags, this means the total cost of them is 7b dollars.

Since she received g dollars in change after paying $90, this implies that 7b < 90 and

g = 90 - 7b

since that's how you compute change (change = amount paid - cost)

Now solve for b

g+=+90+-+7b

g+-+90++=+-7b

-7b+=+g+-+90

b+=+%28g+-+90%29%2F%28-7%29

b+=+%2890+-+g%29%2F7

So the cost of each bag, in terms of g, is b+=+%2890+-+g%29%2F7

Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
7 bags cost (90-g)
1 bag cost (90-g)/7