Question 675272: Can someone assist in helping with this problem?
3y^2 - 2
_________
3y^2 + 10y - 8
minus
y + 10
________
3y^2 + 10y - 8
minus
y^2 - 6y
_________
3y^2 + 10y - 8
Equals = Found 3 solutions by ReadingBoosters, stanbon, MathLover1:Answer by ReadingBoosters(3246) (Show Source):
You can put this solution on YOUR website!
...
...
distribute the negatives
...
Combine like terms
...
.....................
Delighted to help.
-Reading Boosters
Website: www.MyHomeworkAnswers.com
Wanting for others what we want for ourselves.
You can put this solution on YOUR website! (3y^2 - 2)/(3y^2 + 10y - 8)
- (y + 10)/(3y^2 + 10y - 8)
- (y^2 - 6y)/(3y^2 + 10y - 8)
-------------------------------------
The denominators are all the same, so combine the numerators
over the common denominator::
---
= [3y^2-2-y-10-y^2+6y]/(3y^2+10y-8)
----
= (2y^2 +5y -12)/(3y^2+10y-8)
----
Factor:
= (2y^2+8y-3y-12)/(3y^2+12y-2y-8)
-----
= (2y(y+4)-3(y+4))/(3y(y+4)-2(y+4))
-----
= [(y+4)(2y-3)]/[(y+4)(3y-2)]
-------
= (2y-3)/(3y-2)
========================
cheers,
Stan H.
(