SOLUTION: HI...MI NAME IN ANGI AND IM TAKING ALGEBRA AND IT IS A HARD CLASS FOR ME...SO PLEASE MAYBE I CAN LEARN IF YOU EXPLAIN ME HOW...THANKS HERE IS THE PROBLEM 5(X+3)+X=4(X+6)-3 AGAI

Algebra ->  Expressions -> SOLUTION: HI...MI NAME IN ANGI AND IM TAKING ALGEBRA AND IT IS A HARD CLASS FOR ME...SO PLEASE MAYBE I CAN LEARN IF YOU EXPLAIN ME HOW...THANKS HERE IS THE PROBLEM 5(X+3)+X=4(X+6)-3 AGAI      Log On


   



Question 51036: HI...MI NAME IN ANGI AND IM TAKING ALGEBRA AND IT IS A HARD CLASS FOR ME...SO PLEASE MAYBE I CAN LEARN IF YOU EXPLAIN ME HOW...THANKS
HERE IS THE PROBLEM
5(X+3)+X=4(X+6)-3
AGAIN THANK YOU...

Found 2 solutions by stanbon, junior403:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5(X+3)+X=4(X+6)-3
Use the distributive law to get:
5x+15+x = 4x+24-3
Combine like terms to get:
6x+15=4x+21
Move like terms to the same side of the equal sign to get:
2x=6
Divide both sides by 2 to get:
x=3
Cheers,
Stan H.

Answer by junior403(76) About Me  (Show Source):
You can put this solution on YOUR website!
5(X+3)+X=4(X+6)-3
This isnt so bad, it just looks like alot so why dont we just work on one section at a time. lets start with the left side of the equation.
5(x+3)+x
if we follow the order of operations we can use the distributive property with the 5(x+3)+x. this means 5 times x and 5 times 3 + x. Multiply first!
so we get...
5x + 15 + x
does this make sense so far?
now we can add the "like terms" (the x's) together.
5x + x = 6x
so now we have re-written the left side of the equation as...
6x + 15
OK?
Now we put that aside and look at the right side of the original equation.
4(x+6)-3
if we follow the order of operations we can use the distributive property with the 4(x+6)-3. this means 4 times x and 4 times 6 - 3. Multiply first!
so we get...
4x + 24 -3
ok?
now we can combine like terms (the 24 -3).
4x + 21
Good!
now that we have simplified this equation we can put it back together.
6x + 15 = 4x + 21
Does this look a little easier to deal with?
Now we can combine like terms across the equals sign.
We need to isolate the x variables on one side of the equation in order to solve for x. If we subtract the 15 from both sides and we subtract the 4x from both sides we have...
6x - 4x + 15 - 15 = 4x - 4x + 21 - 15
then we can simplify, the 15's cancel on the left and the 4x's cancel on the right...
6x - 4x = 21 - 15
then we combine the terms.
2x = 6
now we can completely isolate the x by dividing both sides by 2...
%282x%29%2F2+=+6%2F2
the 2's cancel out...
x+=+6%2F2
or
x = 3
this is our final answer.
I really hope this helps you out.
Please let me know if you have any questions.
Good Luck!
Alan