SOLUTION: 3x^2 + 4y^2 - ( 5x^2 - 7y^2 - 1) how do I solve this? I am way lost!
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Question 460110
:
3x^2 + 4y^2 - ( 5x^2 - 7y^2 - 1)
how do I solve this? I am way lost!
Answer by
jim_thompson5910(35256)
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3x^2 + 4y^2 - ( 5x^2 - 7y^2 - 1)
3x^2 + 4y^2 - 5x^2 + 7y^2 + 1
(3x^2 - 5x^2) + (4y^2 + 7y^2) + 1
-2x^2 + 11y^2 + 1
So 3x^2 + 4y^2 - ( 5x^2 - 7y^2 - 1) = -2x^2 + 11y^2 + 1