SOLUTION: To prepare for a marathon run, Sue ran 30 miles before she blistered her heel, and then she walked 1 additional mile. Her running speed was 12 times as fast as her walking sp
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Question 1142664: To prepare for a marathon run, Sue ran 30 miles before she blistered her heel, and then she walked 1 additional mile. Her running speed was 12 times as fast as her walking speed. She was running and walking for 7 hours. Find Sue's running speed. Found 4 solutions by Alan3354, josmiceli, josgarithmetic, MathTherapy:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! To prepare for a marathon run, Sue ran 30 miles before she blistered her heel, and then she walked 1 additional mile. Her running speed was 12 times as fast as her walking speed. She was running and walking for 7 hours. Find Sue's running speed.
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r = run speed
w = walk speed
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30/r + 1/w = 7
r = 12w
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30/12w + 1/w = 7
30/12 + 1 = 7w
7w = 3.5
w = 0.5 mi/hr
r = 6 mi/hr
You can put this solution on YOUR website! Let = her walking speed = her running speed
Let = her time spent walking = her time spent running
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(1)
(2)
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(1)
(2)
(2)
(2)
(2) mi/hr
and mi/hr
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check:
(1)
(1)
(1) hrs
and
(2)
(2)
(2)
close enough -check the math
You can put this solution on YOUR website! To prepare for a marathon run, Sue ran 30 miles before she blistered her heel, and then she walked 1 additional mile. Her running speed was 12 times as fast as her walking speed. She was running and walking for 7 hours. Find Sue's running speed.
This is NOT NEARLY as complex as @josmiceli makes it. Plus, his walking speed of 4.298 is WRONG
It's a little more "INVOLVED" if I use S as the running speed, so I'll use S as the walking speed
Then running speed = 12S
We then get:
5 + 2 = 14S ------ Multiplying by LCD, 2S
7 = 14S
S, or walking speed =
Running speed: