SOLUTION: If the first three terms in an arithmetic progression are (x+3), (3x-10) and (2x+10), find x
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Question 1108319
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If the first three terms in an arithmetic progression are (x+3), (3x-10) and (2x+10), find x
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Boreal(15235)
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The difference between adjacent terms is the same
3x-10-(x+3)=2x-13
2x+10-(3x-10)=-x+20
Therefore, 2x-13=-x+20
3x=33
x=11 ANSWER
the terms are 14, 23, and 32, which is an arithmetic progression.