SOLUTION: Given that g(x)=4/x , x is not equal to 0 and fg(x)=2x+3 find the function f. f(4/x)=2x+3 how do i find f(x)???? Help

Algebra ->  Expressions -> SOLUTION: Given that g(x)=4/x , x is not equal to 0 and fg(x)=2x+3 find the function f. f(4/x)=2x+3 how do i find f(x)???? Help      Log On


   



Question 1073536: Given that g(x)=4/x , x is not equal to 0 and fg(x)=2x+3 find the function f.
f(4/x)=2x+3 how do i find f(x)???? Help

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
I am looking in your post and CAN NOT understand, what is your fg(x) = 2x +3 ?

Is it fog(x)     (composition) ?

Or (fg)(x)       (the product of the two functions) ?

Could you clarify ?


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Comment from student: composition.
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My responce. OK, composition.

1.  First of all, it means that your original formulation in the post was wrong.

    The correct writing is  fog(x)=2x+3.

    The composition is always denoted as fog.


2.  Then you can write fog(x) = f(g(x)) = f%284%2Fx%29 = 2x + 3.

    Replace here 4%2Fx by other variable, for example, t.

    You will get f(t) = 2x + 3.

    But since t = 4%2Fx, you have x = 4%2Ft, therefore

    f(t) = 2%2A%284%2Ft%29+%2B+3 = 8%2Ft+%2B+3.


    Now you can replace t in both sides by x (it is simply another symbol for the variable), and you will get f(x) = 8%2Fx+%2B+3.

It is your answer: f(x) = 8%2Fx+%2B+3.

Check. fog(x) = f(g(x) = f%284%2Fx%29 = %288%2F%28%284%2Fx%29%29%29+%2B+3 = %288x%29%2F4%2B3 = 2x + 3. Correct !


Solved.