Problem 1
Andrew and Michael each wants to buy a sundae. But Andrew is 2 d ollars short, while Michael is 1 dollar short.
Combined, they have exactly enough money to buy one sundae. How many dollars does one sundae cost?
Solution
Let x represents the cost of one sundae in dollars. Andrew is $2 short, so he has (x-2) dollars.
Likewise, Michael has (x-1) dollars. Since together they have exactly enough to buy one sundae, x dollars, we can write:
(x-2) + (x-1) = x.
Solve it for x
2x - 3 = x,
2x - x = 3,
x = 3.
ANSWER. Each sundae costs 3 dollars.
Problem 2
Lola, Michael and Joaquin each want to buy a sundae. But Lola is 4 dollars short, Michael is 3 dollars short,
and Joaquin is 1 dollar short. Combined, they have exactly enough money to buy one sundae. How many dollars does one sundae cost?
Solution
Let x represents the cost of one sundae in dollars. Lola is $4 short, so she must have (x-4) dollars.
Likewise, Michael has (x-3) dollars and Joaquin has (x-1). Since together they have exactly enough to buy one sundae, x dollars, we can write:
(x-4) + (x-3) + (x-1) = x.
Solve it for x
3x - 8 = x
3x - x = 8
2x = 8
x = 8/2 = 4.
ANSWER. Each sundae costs 4 dollars.
Problem 3
Mr. Lee wants to buy 5 shirts. If he buys 3 shirts, he will have $6 left. If he gets all of them, he will be $10 short.
How much money does Mr. Lee have?
Solution
In accordance with the context of the problem, all the shirts have the same price.
Let x be the price for one shirt.
Then Mr. Lee has, from one part of the condition, 3x + 6 dollars;
from the other part of the condition, he has 5x - 10 dollars.
It gives you THIS EQUATION
3x + 6 = 5x - 10.
Simplify and find x
6 + 10 = 5x - 3x
16 = 2x
x = 16/2 = 8 dollars.
One shirt costs 8 dollars.
Hence, Mr Lee has 3x + 6 = 3*8 + 6 = 30 dollars. ANSWER
Problem 4
Bob and John want to buy a gift. But Bob is $20 short, while John is $34 short.
Combined, they are $4 short. What is the cost of gift ?
Solution
Let x be the price of the gift, in dollars.
Since Bob is 20 dollars short, he has x-20 dollars;
similarly, John has x-34 dollars.
Altogether, they have (x-20) + (x-34) = 2x-54.
It is exactly x-4 dollars (since altogether they are 4 dollars short)
2x- 54 = x - 4.
From this equation,
x = 54 - 4 = 50.
ANSWER. The gift costs 50 dollars.
Problem 5
A group of office workers had some prize money to distribute among themselves.
When all but one took $9 each, the last person only received $5.
When they all took $8 each, there was $12 left over. How much had they won?
Solution
Let n be the number of workers.
We can express the total money in two different ways.
One way is the total money = 9*(n-1) + 5
Another way is the total money = 8*n + 12.
Since the total money is the same,
9*(n-1) + 5 = 8n + 12
Simplify and find n
9n - 9 + 5 = 8n + 12
9n - 4 = 8n + 12
9n - 8n = 12 + 4
n = 16.
So, there are 16 workers, and the total prize money is 8n+12 = 8*16 + 12 = 140 dollars. ANSWER
My other lessons on solving single linear equations and word problems in one unknown are
- HOW TO solve a linear equation
- Simple word problems to solve using a single linear equation
- More complicated word problems to solve using a single linear equation
- Typical word problems to solve using a single linear equation
- Typical problems on buying and selling items
- Typical investment problems
- Advanced word problems to solve using a single linear equation
- HOW TO algebraize and solve these problems using one equation in one unknown
- Challenging word problems to solve using a single linear equation
- Selected word problems to solve by reducing to single linear equation
- Solving some business-related problems
- HOW TO solve these simple word problems MENTALLY without using equations
- Using time equation to solve some Travel and Distance problems
- Using price equation to solve some business related problems
- Solving problems by the backward method
- Solving more complicated problems by the backward method
- OVERVIEW of lessons on solving linear equations and word problems in one unknown
in this site.