Lesson SOLVE AN EQUATION WITH PARENTHESES
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To solve an equation such as <CENTER>5(x + 3) = 3x + 23,</CENTER> the goal is to bring all the terms involving x over to the left side of the equals sign, and all the other terms over to the right. What we have: expression with x's & numbers = expression with x's & numbers what we want: expression with x's only = expression with numbers only This equation has parentheses on the left, though, so we need to get rid of them first by distributing. After distributing, <CENTER>5(x + 3) = 3x + 23</CENTER> changes to <CENTER>5x + 15 = 3x + 23.</CENTER> Now we're ready to get all the x's on the left and the numbers on the right. Subtract 3x from both sides (this brings all the x's to the left), <CENTER>5x + 15 - 3x = 3x + 23 - 3x,</CENTER> and simplify: <CENTER>2x + 15 = 23.</CENTER> Now subtract 15 from both sides (this brings all the numbers to the right). <CENTER>2x + 15 -15 = 23 - 15,</CENTER> and simplify: <CENTER>2x = 8.</CENTER> Now we got what we wanted! (expression with x's only = expression with numbers only) The final step is to simplify. Dividing both sides by 2 gives <CENTER>2x/2 = 8/2,</CENTER> which simplifies to <CENTER>x = 4.</CENTER> The best way to remember all this is to <a href = "http://www.mathick.com/mathick.php?topic=lineq3">try some out</a>! Click on the <a href = "http://www.mathick.com/mathick.php?topic=lineq3">link</a> for step by step help working through any problem like this.