SOLUTION: Solve the following for the variable "b". Please note that the variables are "a" and "A" are different and unique variables. A = 1/2 h(a + b) This is what I came up with am

Algebra ->  Equations -> SOLUTION: Solve the following for the variable "b". Please note that the variables are "a" and "A" are different and unique variables. A = 1/2 h(a + b) This is what I came up with am       Log On


   



Question 99774: Solve the following for the variable "b". Please note that the variables are "a" and "A" are different and unique variables.
A = 1/2 h(a + b)
This is what I came up with am I on the right track??
A = ½ ha + ½ hb
A- ½ ha / ½ h = ½ hb / ½ h
A – a = b

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following for the variable "b". Please note that the variables are "a" and "A" are different and unique variables.
A = 1%2F2h%28a+%2B+b%29
This is what I came up with am I on the right track??
A = ½ ha + ½ hb

That was OK but not this:

A- ½ ha / ½ h = ½ hb / ½ h
A – a = b

A = 1%2F2h%28a+%2B+b%29

A = 1%2F2ha + 1%2F2hb

Next, clear of fractions by multiplying every
term on both sides by LCD = 2:

2·A = 2·1%2F2ha + 2·1%2F2hb

2A = ha + hb

Get the only term containing b alone on the right by
subtracting ha from both sides:

2A+-ha = hb

Divide both sides by the coefficient of b, which is h:

%282A+-ha%29%2Fh = %28hb%29%2Fh

Cancel only the h's on the right:

%282A+-ha%29%2Fh = b

That is the answer.  Do not cancel the h's
on the left side because h is not a factor
of the numerator but only a factor of one term
of the numerator.

Answer:

b = %282A+-ha%29%2Fh

Edwin