SOLUTION: As part of an exercise how would one get the reverse (antiderivative) of {{{e^(x/9)}}} and the reverse of {{{ e^(2x) }}}
The last one I was just curious about.
My problem state
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-> SOLUTION: As part of an exercise how would one get the reverse (antiderivative) of {{{e^(x/9)}}} and the reverse of {{{ e^(2x) }}}
The last one I was just curious about.
My problem state
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Question 997555: As part of an exercise how would one get the reverse (antiderivative) of and the reverse of
The last one I was just curious about.
My problem states to determine the functions with these conditions.
f'(x) = e^(x/9)
f(0)=19
f(x)=Ae^(bx)+c
My teacher said we cannot use integrals to solve. I am unsure what this question is asking me to do exactly.
Please help
Thank you Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! As part of an exercise how would one get the reverse (antiderivative) of and the reverse of
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(d/dx)9e^(x/9) + C = e^(x/9)
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The last one I was just curious about.
My problem states to determine the functions with these conditions.
f'(x) = e^(x/9)
f(0)=19
f(x)=Ae^(bx)+c
---
f(0) = e^(0)*9 + C = 19
C = 10
--> f(x) = 9e^(x/9) + 10
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My teacher said we cannot use integrals to solve. I am unsure what this question is asking me to do exactly.
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The anti-derivative is the integral. Not sure what that means about not using integrals.
