SOLUTION: Kofi bought six books and ten pencils from a store. Ama bought three books and twenty-two pencils of the same kind from that store. If each of them paid 17000 for the iterms, find

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Question 995988: Kofi bought six books and ten pencils from a store. Ama bought three books and twenty-two pencils of the same kind from that store. If each of them paid 17000 for the iterms, find the cost of
a. Each pencil
b. Each book
c. Two books and four pencils
THANK YOU

Found 3 solutions by josgarithmetic, josmiceli, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = the cost of 1 pencil
Let +b+ = the cost of 1 book
---------------------------
(1) +6b+%2B+10a+=+17000+
(2) +3b+%2B+22a+=+17000+
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Multiply both sides of (2) by +2+
and subtract (1) from (2)
(2) +6b+%2B+44a+=+34000+
(1) +-6b+-+10a+=+-17000+
-------------------------
+34a+=+17000+
+a+=+500+
and
(1) +6b+%2B+10a+=+17000+
(1) +3b+%2B+5a+=+8500+
(1) +3b+%2B+5%2A500+=+8500+
(1) +3b+=+8500+-+2500+
(1) +3b+=+6000+
(1) +b+=+2000+
------------------
Each book costs 2000
Each pencil costs 500
----------------------
You can check by plugging these
results back into (1) and (2)

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Kofi bought six books and ten pencils from a store. Ama bought three books and twenty-two pencils of the same kind from that store. If each of them paid 17000 for the iterms, find the cost of
a. Each pencil
b. Each book
c. Two books and four pencils
THANK YOU
Let price of 1 book be B, and 1 pencil: P
Then we get: 6B + 10P = 17,000 ------- eq (i)
Also, 3B + 22P = 17,000 ------- eq (ii)
To solve:
1) Multiply eq (ii) by - 2 to get eq (iii)
2) Add eqs (iii) & (1), which will eliminate B and give the value of P, or 1 pencil
3) Substitute value for P into any of the 2 original equations to solve and determine the value of B: a book