SOLUTION: Two cyclists, 45 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 3 hours later, what is the speed (in mi/h) of t
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-> SOLUTION: Two cyclists, 45 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 3 hours later, what is the speed (in mi/h) of t
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Question 993904: Two cyclists, 45 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 3 hours later, what is the speed (in mi/h) of the faster cyclist? Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! The easy way: They cover 45 miles in 3 hours. Their combined speed must be 15 miles an hour. Thus the slower guy travels at 5 mph and the faster at 10 mph.
The harder way: If we call the rate of the slower rider R, the faster rider travels at 2R. Since they travel the same 3 hours, one guy travels 3R miles and the other travels 6R miles. Added together, they cover 45 miles, or
3R + 6R = 45
9R = 45
R = 5
2R = 10 miles per hour
