SOLUTION: what is the equation of a line perpendicular to y= 6x-7 and passing through (12,4)

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Question 993007: what is the equation of a line perpendicular to y= 6x-7 and passing through (12,4)
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Slope of the given line is 6, so the line perpendicular to the given line has slope -1%2F6.

The equation you are looking for in POINT-SLOPE form is y-4=-%281%2F6%29%28x-12%29. You can transform this into the form you want if desired or necessary.