Question 989338: Certain chemotherapy dosages depend on a patient's surface area. According to the Mosteller model
S = √(h*M) / 6
where h is the patient's height in m, M is the patient's mass in kg and S is the patient's approximate surface area in m^2. Assume that the patient's height is a constant 187 cm but he is on a diet. If a patient loses 3.1 kg per month, how fast is his surface area changing (in m^2/month) at the instant his mass is 71 kg?
Give your answer correct to 4 decimal places.
Note. You may be wondering why we have referred to the patient's mass here, rather than his weight. Technically, a person's weight is a force (recall: F = Ma, where F is the force, M is the mass, and a is the acceleration, which in this case is g, the acceleration due to gravity). Force (and therefore weight) is measured in Newtons, not kilograms. Scientists, and you are one, should know that. (In orbit, an astronaut experiences weightlessness, not masslessness.)
I am so confused!
Initial = S = √(187*71) / 6 = 19.2043
After One month = S = √(187*69.7) / 6 = 19.0277
I am not sure how to put these together?
THANK YOU
Answer by solver91311(24713)   (Show Source):
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