SOLUTION: Let {{{ f(x) = x^3 + 11 }}} and {{{ a = 3 }}}
Find and simplify the quotient:
{{{ (f(x)-f(a))/(x - a) }}} =
Then find the slope {{{ M[a] }}} of the line tangent to th
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-> SOLUTION: Let {{{ f(x) = x^3 + 11 }}} and {{{ a = 3 }}}
Find and simplify the quotient:
{{{ (f(x)-f(a))/(x - a) }}} =
Then find the slope {{{ M[a] }}} of the line tangent to th
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You can put this solution on YOUR website! .
Hello,
your post was written incorrectly from the Perl's point of view.
I corrected and saved it.
You can submit it again with my corrections.
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OK. Now I am continuing to solve it.
f(x) - f(a) = - = = .
= = .
It is the expression for for the slope of the tangent line to the curve = in vicinity of the point (a,f(a).
If the point x tends to the point a, then the slope tends to = .