SOLUTION: Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is egual to 742

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Question 984682: Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is egual to 742
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let the four consecutive integers be given by
N, N+2, N+4 and N+6
You are told that N+%2B+%28N%2B2%29+%2B+2%2A%28%28N%2B4%29%2B%28N%2B6%29%29+=+742
Solve for N
N+%2B+N+%2B+2+%2B+2N%2B8+%2B2N%2B12+=+742
6N+%2B+22+=+742
6N+=+720
N+=+120
So the numbers are 120, 122, 124, and 126
Check your answer. is 742+=+120%2B122+%2B+2%28124%2B126%29