SOLUTION: does t^2 = m^4pi^2R * (R^2/GmM) become t^2 = (m^4pi^2R^3/GmM) into t^2 = (m^3pi^2R^3/GM) so that t = square root of (m^3pi^2R/GM) ?

Algebra ->  Equations -> SOLUTION: does t^2 = m^4pi^2R * (R^2/GmM) become t^2 = (m^4pi^2R^3/GmM) into t^2 = (m^3pi^2R^3/GM) so that t = square root of (m^3pi^2R/GM) ?      Log On


   

Question 983412: does
t^2 = m^4pi^2R * (R^2/GmM)
become
t^2 = (m^4pi^2R^3/GmM)
into
t^2 = (m^3pi^2R^3/GM)
so that
t = square root of (m^3pi^2R/GM)
?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Almost. Watch the cancellations and square root extractions carefully.

t=m%2Api%2Asqrt%28%28mR%29%2F%28GM%29%29

Unsure if you needed to take more care about parentheses for grouping to express what you have.
Exactly what is your starting equation? That's what is not clear.