SOLUTION: Please help me solve this equation. 2(3n(n-2)) = 3(2n(n-1)+12
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Question 980171
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Please help me solve this equation.
2(3n(n-2)) = 3(2n(n-1)+12
Answer by
ikleyn(52777)
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2(3n(n-2)) = 3(2n(n-1) + 12,
2*(3n^2 - 6n) = 3*(2n^2 -2n) + 12,
6n^2 - 12n = 6n^2 - 6n + 12.
-6n = 12.
n = -2.
Check
: Left side is 2*3*(-2)*(-4) = 48. Right side is 3*2*(-2)*(-3) + 12 = 36 + 12 = 48. Both sides are the same.
Answer
. The solution is n = -2.