SOLUTION: solve for x; determine if solution is real or extraneous 2x/4 + 3x/5 = 1/20 x/x+1 + x^2/2x+2 - 1/-x-1 = 1

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Question 979062: solve for x; determine if solution is real or extraneous
2x/4 + 3x/5 = 1/20
x/x+1 + x^2/2x+2 - 1/-x-1 = 1
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%282x%29%2F4+%2B+%283x%29%2F5+=+1%2F20
Multiply both sides by 20.
10x%2B12x=1
22x=1
x=1%2F22
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.
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x%2F%28x%2B1%29%2Bx%5E2%2F%282x%2B2%29-1%2F%28-x-1%29=1
x%2F%28x%2B1%29%2B%28x%5E2%2F2%29%281%2F%28x%2B1%29%29%29%2B1%2F%28x%2B1%29=1
Multiply both sides by 2%28x%2B1%29
2x%2Bx%5E2%2B2=2%28x%2B1%29
2x%2Bx%5E2%2B2=2x%2B2
x%5E2=0
x=0