SOLUTION: Solve for h. S= 2 Pi rh + 2 Pi r(to the 2nd power) Here's what I got. S = h --------- 2 Pi r + 2 Pi r(to the 2nd

Algebra ->  Equations -> SOLUTION: Solve for h. S= 2 Pi rh + 2 Pi r(to the 2nd power) Here's what I got. S = h --------- 2 Pi r + 2 Pi r(to the 2nd       Log On


   

Question 97695This question is from textbook intro alg blitzer
: Solve for h.

S= 2 Pi rh + 2 Pi r(to the 2nd power)
Here's what I got.
S = h
---------
2 Pi r + 2 Pi r(to the 2nd power)
Am I missing a step or is this correct?
 This question is from textbook intro alg blitzer

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for h:
S+=+2%28pi%29rh%2B2%28pi%29r%5E2 Subtract 2%28pi%29r%5E2 from both sides.
S-2%28pi%29r%5E2+=+2%28pi%29rh Now divide both sides by 2%28pi%29r
%28S-2%28pi%29r%5E2%29%2F2%28pi%29r+=+h