SOLUTION: The length of a conference room is one and a half times its width. A carpet that is twice as long as it is wide is placed in the centre of the room, leaving a 3m wide border round

Algebra ->  Equations -> SOLUTION: The length of a conference room is one and a half times its width. A carpet that is twice as long as it is wide is placed in the centre of the room, leaving a 3m wide border round       Log On


   



Question 975122: The length of a conference room is one and a half times its width. A carpet that is twice as long as it is wide is placed in the centre of the room, leaving a 3m wide border round the carpet. Find the area of the carpet.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
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The description switches directions of the dimensions, but doing that makes the description distracting. Both the room and the carpet are twice as long as they are wide.

x, a factor to help relate "length and width" for the carpet, also for the room.

x and 2x are the dimensions of the carpet, for 2x the length, x the width.
x%2A2x=AreaOfCarpet=2x%5E2.
%28x%2B2%2A3%29%282x%2B2%2A3%29=RoomArea.

You can not really find a value for the carpet area. The room area is not given nor findable; the carpet area is not given nor findable; the border area is neither.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The length of a conference room is one and a half times its width. A carpet that is twice as long as it is wide is placed in the centre of the room, leaving a 3m wide border round the carpet. Find the area of the carpet.
Width of carpet: 6 units
Carpet’s length: 2(6), or 12 units
Carpet’s area: 6(12), or highlight_green%2872%29 sq units