SOLUTION: question 1
Find a linear model and use it to make a prediction
7. A 2 mile cab ride costs $5.25. A 5 mile cab ride cost $10.50. How much does a 3.8 mile cab ride cost?
I f
Algebra ->
Equations
-> SOLUTION: question 1
Find a linear model and use it to make a prediction
7. A 2 mile cab ride costs $5.25. A 5 mile cab ride cost $10.50. How much does a 3.8 mile cab ride cost?
I f
Log On
Question 97050This question is from textbook prentice hall-algebra 2
: question 1
Find a linear model and use it to make a prediction
7. A 2 mile cab ride costs $5.25. A 5 mile cab ride cost $10.50. How much does a 3.8 mile cab ride cost?
I figured out the answer is y=1.75x+1.75
But I have no idea how to solve it.
Question 2
Suppose f(x)= 2x+5 and g(x)= -1/3x + 2 find each value. (Hint: For 2g(x), find g(x) first and then mulitiply the result by 2
You can put this solution on YOUR website! ANS 1
Since it is given that the cost is a linear representation of distance
let us represent the cost C = k*m + A ( similar to y=mx +c)
where k is the coefficient of m ( the miles travelled) and A a constant factor
A 2 mile cab ride costs $5.25.
5.25 = k*2 + A .......(2)
A 5 mile cab ride cost $10.50
10.50 = k*5 + A ........(3)
Subtractin (2) from (3)
5.25 = 3k
k = 5.25/3 =1.75
Substituting k in (2)
5.25 = 1.75*2 + A
A= 5.25 - 3.50= 1.75
Putting the values of k and A in (1)
we have the Cost C= 1.75m + 1.75 where m is the distance covered.
ANS 2 given f(x)= 2x+5 and g(x)= -1/3x + 2
to evaluate f(-2) / g(f(-2)+1)
we have f(-2) = 2* (-2) +5 =1
now g(f(-2)+1)
=g(1+1) putting the value of f(-2) from above
=g(2) = -1/3*2 + 2
=-1/6 +2
=11/6
f(-2) / g(f(-2)+1) = 1/(11/6)= 6/11
