SOLUTION: how do i write an equation for Line p contains point (6,-5) and is perpendicular to line q. The equation for line q is y = 3x + 5.
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Question 969123: how do i write an equation for Line p contains point (6,-5) and is perpendicular to line q. The equation for line q is y = 3x + 5. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how do i write an equation for Line p contains point (6,-5) and is perpendicular to line q. The equation for line q is y = 3x + 5.
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Line q has slope = 3
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Any line perpendicular to q must have slope = -1/3
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Form::
y = mx + b
Solve for "b"::
-5 = (-1/3)6 + b
-5 = -2 + b
b = -3
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Equation you want::
y = (-1/3)x - 3
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Cheers,
Stan H.
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