Question 967582: find the equation of the line which passes through the point ( -2, 1 ) and is parallel to the straight line with the equation 2x - y - 3 = 0?
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! find the equation of the line which passes through the point ( -2, 1 ) and is parallel to the straight line with the equation 2x - y - 3 = 0?
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2x - y - 3 = 0
To find the slope, convert to slope-intercept form.
That means solve for y.
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2x - y - 3 = 0
y = 2x - 3
The slope, m, is the coefficient of x.
m = 2
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Parallel lines have the same slope. 2, in this case.
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An equation, not "the equation," is y - y1 = m*(x - x1)
(x1,y1) is (-2,1) PS don't put spaces in the points.
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y - 1 = 2*(x + 2)
You can change the format.
y = 2x + 5
Same thing.
Answer by MathLover1(20849)  (Show Source):
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