SOLUTION: How many lbs of a 20% copper alloy must be mixed with 600lbs of a 30% copper alloy to make a 27.5% copper alloy?

Algebra ->  Equations -> SOLUTION: How many lbs of a 20% copper alloy must be mixed with 600lbs of a 30% copper alloy to make a 27.5% copper alloy?       Log On


   

Question 96456This question is from textbook Algebra Beginning and Intermediate
: How many lbs of a 20% copper alloy must be mixed with 600lbs of a 30% copper alloy to make a 27.5% copper alloy?
 This question is from textbook Algebra Beginning and Intermediate

Answer by rossiv53(27) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the amount of 20% copper alloy
20%x+30%(600)=27.5%(x+600)
.20x%2B.30%28600%29=.275%28x%2B600%29
.20x%2B180=.275x%2B165
.20x-.275x%2B180=.275x%2B165-.275x
-.075x%2B180=165
-.075%2B180-180=165-180
-.075=-15
x=200
x=200 lbs
Good Luck!