SOLUTION: The question is: find three consecutive intengers whose sum is 11 less than 5 times the smallest of the three. I think the equation would be x+y+z=5x-11 but how do I solve it?

Algebra ->  Equations -> SOLUTION: The question is: find three consecutive intengers whose sum is 11 less than 5 times the smallest of the three. I think the equation would be x+y+z=5x-11 but how do I solve it?      Log On


   

Question 96128: The question is: find three consecutive intengers whose sum is 11 less than 5 times the smallest of the three.
I think the equation would be x+y+z=5x-11 but how do I solve it?
Help!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
you are on the right track

consecutive integers means y is one more than x and z is one more than y ... so x+(x+1)+(x+2)=5x-11

3x+3=5x-11 ... 14=2x ... 7=x