SOLUTION: if the length of a rectangle is four less than twice its width and the area is 48 meters squared find the length and the width

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Question 960000: if the length of a rectangle is four less than twice its width and the area is 48 meters squared find the length and the width
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
W=width; L=length=2W-4; A=area=48 sq m
A=L%2AW Substitute for L
A=%282W-4%29%28W%29
48m%5E2=2W%5E2-4W Divide each side by 2.
24m%5E2=W%5E2-2W Subtract 24 sq m from each side.
0=W%5E2-2W-24
0=%28W-6%29%28W%2B4%29
W-6=0 or W%2B4=0
W=6 or W=-4 ANSWER 1: The width is 6 meters.
L=2W-4m=2%286m%29-4m=12m-4m=8m ANSWER 2: The length is 8 meters.
CHECK:
A=L%2AW
48m%5E2=%288m%29%286m%29
48m%5E2=48m%5E2