Question 959335: Three more than the square root of the sum of 3 consecutive odd numbers is 12. Find the three numbers. Found 2 solutions by macston, checkley77:Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! n,n+2,and n+4 are consecutive odd integers Subtract 3 from each side. Square each side. Subtract 6 from each side. Divide each side by 3. ANSWER 1: The first odd number is 25 = ANSWER 2: The second number is 27. = ANSWER 3: The third number is 29.
CHECK:
You can put this solution on YOUR website! SQRT(X+X+2+X+4)+3=12
SQRT(3X+6)=12-3
SQRT(3X+6)=9 SQ BOTH SIDES
3X+6=81
3X=81-6
3X=75
X=75/3
X=25 ANS. FOR THE FIRST ODD NUMBER
25+2=27 FOR THE SECOND NUMBER.
25+4=29 FOR THE THIRD NUMBER.
PROOF:
SQRT(25+27+29)+3=12
SQRT81+3=12
9+3=12
12=12