SOLUTION: 3x^2-2y^2=5 2x^2-y^2=-2 how to solve this system by the elimination method?

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Question 958362: 3x^2-2y^2=5
2x^2-y^2=-2
how to solve this system by the elimination method?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply the second equation by (-2) and add the equations together,
3x%5E2-2y%5E2-4x%5E2%2B2y%5E2=5%2B4
-x%5E2=9
x%5E2=-9
x=0+%2B-+3i
So then,
2%28-9%29-y%5E2=-2
-18-y%5E2=-2
y%5E2=-16
y=0+%2B-+4i