SOLUTION: Please help me solve this equation: {{{ (a-2)*x^2=0 }}} a≠2 ; result= double 0 Thank you.

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Question 952486: Please help me solve this equation: +%28a-2%29%2Ax%5E2=0+ a≠2 ; result= double 0
Thank you.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
+%28a-2%29%2Ax%5E2=0+
a%3C%3E2 ; result= double 0
you will get result= double 0 for any value of a+ you choose because %28a-2%29 is actually coefficient in front of variable x

example:
+%28a-2%29%2Ax%5E2=0+ if a=-5
+%28-5-2%29%2Ax%5E2=0+
+-7x%5E2=0+
solution: result= double 0
+%28a-2%29%2Ax%5E2=0+ if a=5
+%285-2%29%2Ax%5E2=0+
+3x%5E2=0+
solution: result= double 0
recall discriminant b%5E2-4ac:
the rule: if b%5E2-4ac=0, there will be 1 double 0, or one real root
in your case +%28a-2%29%2Ax%5E2=0+
the value for a is actually a-2,b=0, and c=0
0%5E2-4%28a-2%29%2A0=0
0-4%28a-2%29%2A0=0=> no matter what you put for a you will get
0=0