SOLUTION: Center is (3,2); a=3c; foci:(1,2),(5,2)

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Question 952225: Center is (3,2); a=3c; foci:(1,2),(5,2)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
given:
Center is (3,2);
a=3c;
foci:(1,2),(5,2)

the equation of the ellipse is:
%28x-h%29%5E2%2Fa%5E2%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
so, for your ellipse it is:
%28x-3%29%5E2%2Fa%5E2+%2B+%28y-2%29%5E2%2Fb%5E2+=+1 (center at (3,2), means h=3 and h=2)

for an ellipse,+a%5E2+-b%5E2+=+c%5E2
because the foci have the same y-coordinate, you know that it is a horizontal ellipse (major axis is horizontal)
distance from (1,2) to (5,2) =+2c , where c is the distance from the center to each focus

2c+=+4+==> c+=+2 (which is also the distance from (3,2) to either (1,2) or (5,2))

since a+=+3c, that means that a+=+3%2A2+=+6


then, b%5E2=+6%5E2+-+2%5E2 => b%5E2=36+-+4}}} =>+b%5E2=32
and your equation is:
%28x+-+3%29%5E2+%2F+36+%2B+%28y+-+2%29%5E2+%2F+32+=+1+