SOLUTION: Write the equation of a line that is perpendicular to the given line and that passes through the given point.
–x + 5y = 14; (–5, –2)
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-> SOLUTION: Write the equation of a line that is perpendicular to the given line and that passes through the given point.
–x + 5y = 14; (–5, –2)
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Question 950830: Write the equation of a line that is perpendicular to the given line and that passes through the given point.
–x + 5y = 14; (–5, –2) Answer by amarjeeth123(569) (Show Source):
You can put this solution on YOUR website! The equation of the line is –x + 5y = 14
5y=x+14
y=1/5x+14/5
Slope of the line=1/5
Slope of a line perpendicular to the line=-5
The equation of the line is y=mx+c
y=-5x+c
Since the line passes through (-5,-2)
-2=25+c
c=-27
The equation of the line is y=-5x-27
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