SOLUTION: Find the minimum y-value located on the graph of y=2x^2-6x+1.

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Question 947506: Find the minimum y-value located on the graph of y=2x^2-6x+1.
Found 3 solutions by josgarithmetic, MathTherapy, rfer:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
NOTE: Fixed one mistake.


Check the lesson on this.

y=2%28x%5E2-3x%29%2B1
y=2%28x%5E2-3x%2B%283%2F2%29%5E2%29%2B1-2%2A%283%2F2%29%5E2
y=2%28x-3%2F2%29%5E2%2B4%2F4-18%2F4
highlight%28y=2%28x-3%2F2%29%5E2-14%2F4%29
highlight%28y=2%28x-3%2F2%29%5E2-7%2F2%29

NOW find the minimum value!

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Find the minimum y-value located on the graph of y=2x^2-6x+1.
y+=+2x%5E2+-+6x+%2B+1

Its minimum will occur at the x-coordinate of the vertex, or the axis of symmetry, or where: x+=+-+b%2F2a.

When found, substitute this x-value into the equation to get y: the minimum value.

Answer by rfer(16322) About Me  (Show Source):