SOLUTION: Find the minimum y-value located on the graph of y= -3x^2+2x-5.

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Question 947501: Find the minimum y-value located on the graph of y= -3x^2+2x-5.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Use Completing The Square to put the equation into standard form:
Completing the Square to Solve General Quadratic Equation

Read the vertex point directly from the standard form equation, y=a%28x-h%29%5E2%2Bk, which would show k to be the maximum value for your equation. Note carefully, YOUR given equation will have a MAXIMUM, not a minimum.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the minimum y-value located on the graph of y= - 3x^2+2x-5.
y+=+-+3x%5E2+%2B+2x+-+5

This graph will have a MAXIMUM (leading coefficient < 0), not a MINIMUM.



Maximum will occur at the x-coordinate of the vertex, or the axis of symmetry, or at: x+=+-+b%2F2a.

When found, substitute this x-value into the equation to get  y, the MAXIMUM value.