SOLUTION: How would I use the elimination method to for this equation? -2x+y=2 3x-y=3

Algebra ->  Equations -> SOLUTION: How would I use the elimination method to for this equation? -2x+y=2 3x-y=3      Log On


   

Question 938456: How would I use the elimination method to for this equation?
-2x+y=2
3x-y=3
Found 3 solutions by algebrahouse.com, MathLover1, rothauserc:
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
-2x + y = 2
3x - y = 3
-----------
x = 5 {added the two equations together}

-2x + y = 2 {top original equation}
-2(5) + y = 2 {substituted 5, in for x, into top original equation}
-10 + y = 2 {multiplied}
y = 12 {added 10 to each side}

x = 5 and y = 12

For more help from me, visit: www.algebrahouse.com

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

-2%2Ax%2B1%2Ay=2
3%2Ax-1%2Ay=3

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -2 and 3 to some equal number, we could try to get them to the LCM.

Since the LCM of -2 and 3 is -6, we need to multiply both sides of the top equation by 3 and multiply both sides of the bottom equation by 2 like this:

3%2A%28-2%2Ax%2B1%2Ay%29=%282%29%2A3 Multiply the top equation (both sides) by 3
2%2A%283%2Ax-1%2Ay%29=%283%29%2A2 Multiply the bottom equation (both sides) by 2


So after multiplying we get this:
-6%2Ax%2B3%2Ay=6
6%2Ax-2%2Ay=6

Notice how -6 and 6 add to zero (ie -6%2B6=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%28-6%2Ax%2B6%2Ax%29%2B%283%2Ay-2%2Ay%29=6%2B6

%28-6%2B6%29%2Ax%2B%283-2%29y=6%2B6

cross%28-6%2B6%29%2Ax%2B%283-2%29%2Ay=6%2B6 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

1%2Ay=12

y=12 Divide both sides by 1 to solve for y



y=12 Reduce


Now plug this answer into the top equation -2%2Ax%2B1%2Ay=2 to solve for x

-2%2Ax%2B1%2812%29=2 Plug in y=12


-2%2Ax%2B12=2 Multiply



-2%2Ax=2-12 Subtract 12 from both sides

-2%2Ax=-10 Combine the terms on the right side

cross%28%281%2F-2%29%28-2%29%29%2Ax=%28-10%29%281%2F-2%29 Multiply both sides by 1%2F-2. This will cancel out -2 on the left side.


x=5 Multiply the terms on the right side


So our answer is

x=5, y=12

which also looks like

(5, 12)

Notice if we graph the equations (if you need help with graphing, check out this solver)

-2%2Ax%2B1%2Ay=2
3%2Ax-1%2Ay=3

we get



graph of -2%2Ax%2B1%2Ay=2 (red) 3%2Ax-1%2Ay=3 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (5,12). This verifies our answer.

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
-2x +y = 2
3x -y = 3
add the two equations, then
x = 5 and
-2*5 +y = 2
-10 +y = 2
y = 12
solution set is x = 5, y = 12
check answers
3*5 -12 = 3
15 -12 = 3
3 = 3
our answers check