Multiply both members of either or both equations to make the coefficients of either variable become equal in their absolute value. Read and reread that again thinking carefully.
Try elimination of t.
5 and 3 are factors to use to do this:
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5(5r+3t)=5(-1)
25r+15t=-5
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3(-2r-5t)=3(-11)
-6r-15t=-33
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resulting system .
These are two equations. If you have something like D=F, and then do
D+k=F+k, then this equation is equivalent to D=F.
Also, if you have k=m, then you can do
D+k=F+m, and this too is equivalent to D=F.
That would be the use of the substitution operation from a system like .
You will do the same thing for the "resulting system" just found above.
Sum the lefthand members, sum the right hand members, and set them equal. This will eliminate the terms of t...
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You can handle the other variable in nearly a similar way.
To eliminate r, starting from the ORIGINAL system, you should choose factors of 2 and 5.
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