SOLUTION: 5y^2+5y-25y-25=0 How do I solve this equation to find out what y is?

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Question 936200: 5y^2+5y-25y-25=0
How do I solve this equation to find out what y is?
Found 2 solutions by MathLover1, rothauserc:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

5y%5E2%2B5y-25y-25=0...as you can see, all terms are divisible by 5; so, we will simplify it first
5y%5E2%2F5%2B5y%2F5-25y%2F5-25%2F5=0
y%5E2%2By-5y-5=0
y%5E2-4y-5=0...factor completely; first write -4y as y-5y
y%5E2%2By-5y-5=0...group
%28y%5E2%2By%29-%285y%2B5%29=0
y%28y%2B1%29-5%28y%2B1%29=0
%28y-5%29%28y%2B1%29=0
so, solutions are:
if %28y-5%29=0 then highlight%28y=5%29
if %28y%2B1%29=0 then highlight%28y=-1%29



Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
5y^2+5y-25y-25=0
5y^2-20y-25=0
divide both sides of = by 5
y^2-4y-5=0
factor polynomial
(y-5)(y+1)=0
y = 5 or -1