SOLUTION: Hello, Please help me write a system of 3 linear equations in 3 variables given the solution set (3,2,-5). I've tried so many times but I just can't get it right. Thank you in ad

Algebra ->  Equations -> SOLUTION: Hello, Please help me write a system of 3 linear equations in 3 variables given the solution set (3,2,-5). I've tried so many times but I just can't get it right. Thank you in ad      Log On


   



Question 935661: Hello,
Please help me write a system of 3 linear equations in 3 variables given the solution set (3,2,-5). I've tried so many times but I just can't get it right. Thank you in advance.

Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me write a system of 3 linear equations in 3 variables given the solution set (3,2,-5).
---
x = 3
y = 2
z = -5
---
x + y + z = 0
x + y + 2z = -5
x +2y + z = 2

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given:
(3,2,-5)=> x=3, y=2, and z=-5

ax%2Bby%2Bcz=r ...we can set a=1, b=1, and c=1, then plug in x=3, y=2, and z=-5, we will have

1%2A3%2B1%2A2-1%2A5=r+
3%2B2-5=r+
5-5=r+
0=r
so, first equation is:
x%2By%2Bz=0.......1
now set a=3, b=2, and c=4, then plug in x=3, y=2, and z=-5, we will have
3%2A3%2B2%2A2%2B4%28-5%29=r
9%2B4-20=r
-7=r
second equation is:
3x%2B2y%2B4z=-7.........2
now set a=1, b=5, and c=-5, then plug in x=3, y=2, and z=-5, we will have
3%2B5%2A2-5%28-5%29=r
3%2B10%2B25=r
38=r
third equation is:
x%2B5y-z=38........3


so, your system is:
x%2By%2Bz=0.......1
3x%2B2y%2B4z=-7.........2
x%2B5y-z=38........3


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