SOLUTION: How would I solve: 2 ^3x-5 = 7
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Question 932841
:
How would I solve: 2 ^3x-5 = 7
Answer by
stanbon(75887)
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2^(3x-5) = 7
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Take the long of both sides::
(3x-5)*log(2) = log(7)
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3x-5 = log(7)/log(2) = 2.807
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3x = 7.807
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x = 2.602
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Cheers,
Stan H.
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