SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
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Question 93267: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs. Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Starting with the perimeter: where s = the length of one of the equal sides and b = the length of the base and P = 29 cm.
But s = 4b-8 s is "8 cm less than 4 times the length of the base"
Substituting 4b-8 for s in the formula for the perimeter: Simplify. Add 16 to both sides. Divide both sides by 9. This is the length of the base, but you need the length of s, so... cm.
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