SOLUTION: PLEASE HELP ME PLEASE IF(4P+1)^2=81 AND P>0,WHAT IA A POSSIBLE VALUE OF P?

Algebra ->  Equations -> SOLUTION: PLEASE HELP ME PLEASE IF(4P+1)^2=81 AND P>0,WHAT IA A POSSIBLE VALUE OF P?      Log On


   

Question 926309: PLEASE HELP ME PLEASE
IF(4P+1)^2=81 AND P>0,WHAT IA A POSSIBLE VALUE OF P?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

if %284P%2B1%29%5E2=81 and P%3E0,...solve for P
%284P%2B1%29%5E2-81=0
%284P%2B1%29%5E2-9%5E2=0
%28%284P%2B1%29-9%29%28%284P%2B1%29%2B9%29=0
%284P%2B1-9%29%284P%2B1%2B9%29=0
%284P-8%29%284P%2B10%29=0
solutions:
if %284P-8%29=0 =>4P=8 =>P=2
if %284P%2B10%29=0 =>4P=-10 =>P=-5%2F2

since given that P%3E0, we can use only P=2 as a possible value for P