SOLUTION: please help me ........... if x is positive integer and (x-6)^2=9,then x^2

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Question 926082: please help me ...........
if x is positive integer and (x-6)^2=9,then x^2
Found 2 solutions by Roseghanezadeh, MathTherapy:
Answer by Roseghanezadeh(16) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
(x - 6) ^ 2 = 9
x - 6 = sqrt(9)
x - 6 = 3
x = 9
So x ^2 = 9^2 = 81

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

please help me ...........
if x is positive integer and (x-6)^2=9,then x^2


%28x+-+6%29%5E2+=+9

x+-+6+=+0+%2B-+sqrt%289%29 ------ Taking square root of both sides

x+-+6+=+0+%2B-+3

x+=+6+%2B-+3

x = 9 or 3

x%5E2+=+9%5E2, or x%5E2+=+3%5E2______highlight_green%28x%5E2+=+system+%2881_or%2C+9%29%29