SOLUTION: PLEASE HELP ME PLEASE IF ANYONE CAN IF(P-Q)^2=25 AND PQ=14,WHAT IS THE VALUE OF (P+Q)^2?

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Question 924373: PLEASE HELP ME PLEASE IF ANYONE CAN
IF(P-Q)^2=25 AND PQ=14,WHAT IS THE VALUE OF (P+Q)^2?

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Let's use lower-case for the variables and try a solution.

%28p-q%29%5E2=25, pq=14, and you want to find %28p%2Bq%29%5E2.

p%5E2-2pq%2Bq%5E2=25, first equation partially simplified;
p%5E2%2Bq%5E2-2pq=25
Substitute using the second equation:
p%5E2%2Bq%5E2-2%2A14=25
p%5E2%2Bq%5E2=25%2B28
p%5E2%2Bq%5E2=53
Another substitution again using from the second equation:
p%5E2%2B%2814%2Fp%29%5E2=53
p%5E4%2B14%5E2=53p%5E2
p%5E4-53p%5E2%2B14%5E2=0
Solution first for p^2.----------------, this method will be long and very detailed...


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Maybe another way.

p-q=0%2B-+5 from the first equation.
-q=-p%2B-+5
highlight_green%28q=p%2B-+5%29.
-
Using this q in the next equation of pq=14,
p%28p-5%29=14
p%5E2-5p-14=0
%28p%2B2%29%28p-7%29=0
p=-2 OR p=7
OR
p%28p%2B5%29=14
p%5E2%2B5p-14=0
%28p-2%29%28p%2B7%29=0
p=2 OR p=-7

Again, looking at the pq=14 equation, p and q must be of the same sign so that their product is POSITIVE 14. This means that their solutions must be:
---------------------------
p=-2 and q=-7
OR
p=2 and q=7.
---------------------------

The exercise question asked for was, find %28p%2Bq%29%5E2.
Using either combination of p and q found, this expression will be highlight%28%282%2B7%29%5E2=9%5E2=highlight%2881%29%29.