Question 924104: PLEASE TELL ME HOW I CAN SOLVE IT,I AM STUCK
(IF 16*A^2*64=(4*B)^2 AND A AND B ARE POSITIVE INTEGERS,THEN B IS HOW MANY TIMES GREATER THAN A?
PLEASE EXPLAIN ME WHAT ARE THEY ASKING FOR AND HOW CAN I SOLVE IT?
Found 2 solutions by ptaylor, MathTherapy:
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! 16*A^2*64=(4*B)^2
16*(A^2)*64=16*B^2 Divide both sides by 16
64*A^2=B^2 Take the square root of both sides
8A=B
The problem asks to determine how many times greater B is than A.
If it takes 8 A's to make 1 B, the B must be 8 times greater than A
Hope this helps--ptaylor
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
PLEASE TELL ME HOW I CAN SOLVE IT,I AM STUCK
(IF 16*A^2*64=(4*B)^2 AND A AND B ARE POSITIVE INTEGERS,THEN B IS HOW MANY TIMES GREATER THAN A?
PLEASE EXPLAIN ME WHAT ARE THEY ASKING FOR AND HOW CAN I SOLVE IT?
B is 7 times GREATER THAN A
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